This stat has been causing a lot of confusion. After a discussion we came to the conclusion that it’s best to have 0 be the breakeven point and add negative values. Every loss should return -1, currently it returns 0. Wins are correct.
An example: facing a pot sized bet (we’re getting 2:1 pot odds):
a) winning one hand and loosing one hand: 2-1=1
b) winning one hand and loosing two hands: 2-1-1=0
c) winning one hand and loosing three hands: 2-1-1-1=-1
Another example: facing a 2x pot bet (we’re getting 3:2 or 1.5:1 pot odds):
a) winning one hand and loosing one hand: 1.5-1=0.5
b) winning one hand and loosing two hands: 1.5-1-1=-0.5
c) winning one hand and loosing three hands: 1.5-1-1-1=-1.5
d) winning four hands and loosing six hands: (1.5*4) – (1*6)= 0
And another example: facing a half pot bet (we’re getting 3:1 pot odds):
a) winning one hand and loosing one hand: 3-1=2
b) winning one hand and loosing two hands: 3-1-1=-1
c) winning one hand and loosing three hands: 3-1-1-1=0
d) winning one hand and loosing four hands: 3-1-1-1-1=-1
Split pot hands currently return 0. They should return half the value it would have been if the pot had been won.
River Call Efficiency
Reply With Quote
Originally Posted by ten25
