Hello HM2 respected team!
I've got a practical question on BB Resteal Stat.
I guess it should be calculated somehow as a weighted average of the BB 3bet vs CO, BB 3bet vs BTN and BB 3bet vs SB stats.
In practice i have BB Resteal stat on one of the opponents which poorly correlates with these 3bet stats.
For instance this opponent has a BB Resteal = 11 (56), i guess it means 11% 3bets vs CO\BTN\SB steals overall on 56 situations sample. Is it right?
On the other hand i see that this same opponent has a BB 3bet vs CO = 13(32), BB 3Bet vs BTN = 4(28) and BB 3bet vs SB = 4(24) (13% out of 32 occasions, 4% out of 28 and 4% of 24 accordingly).
So it looks like he had 32+28+24 = 84 spots to 3bet on BB vs any kind of CO\BTN\SB raises.
I guess these include 3bets from BB vs pure steals (i.e. RFI from CO\BTN\SB) and i suppose also 3bets from BB vs limp-raise situations (where somebody raised from CO\BTN\SB after previous limp).
But does it include spots when somebody raised before CO and then CO or BTN or SB called and then the BB made a 3Bet (type of squeze)? Probably not cause it's already not a 3bet vs CO\BTN\SB?
Could you please explain then how the BB Resteal is calculated mathematically?
Because based on BB 3Bet vs CO\BTN\SB stats i assume
BB Resteal = BB 3Bet vs CO*(vs CO 3Bet share) + BB 3Bet vs BTN*(vs BTN 3Bet share) + BB 3Bet vs SB*(vs SB 3Bet share) = 13%*(32/84) + 4%*(28/84) + 4%*(24/84) = 7,4%.
So it deviates pretty big from the 11% BB resteal stat even though that BB 3Bet vs CO\BTN\SB situations i suppose does not only include 3bets vs steals but also some other cases.