uneducated
05-01-2009, 01:01 AM
The probability that any player will experience a downswing of size b after a total of 100*t hands have been played is,
1 - e^{-2t μ ^2/( α^2(e^{2b μ / α ^2} - 1) - 2b μ)}.
Where,
t = the number of sets of 100 hands
μ = win-rate
α = standard deviation
b = size of the downswing
http://forumserver.twoplustwo.com/32/beginners-questions/standard-variance-5max-nlh-461565/
can anyone code this please?
1 - e^{-2t μ ^2/( α^2(e^{2b μ / α ^2} - 1) - 2b μ)}.
Where,
t = the number of sets of 100 hands
μ = win-rate
α = standard deviation
b = size of the downswing
http://forumserver.twoplustwo.com/32/beginners-questions/standard-variance-5max-nlh-461565/
can anyone code this please?